4b^2-29b+7=0

Solution for 4b^2-29b+7=0 equation:

Simplifying
4b2 + -29b + 7 = 0

Reorder the terms:
7 + -29b + 4b2 = 0

Solving
7 + -29b + 4b2 = 0

Solving for variable 'b'.

Factor a trinomial.
(1 + -4b)(7 + -1b) = 0

Subproblem 1
Set the factor '(1 + -4b)' equal to zero and attempt to solve:

Simplifying
1 + -4b = 0

Solving
1 + -4b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + -1 + -4b = 0 + -1

Combine like terms: 1 + -1 = 0
0 + -4b = 0 + -1
-4b = 0 + -1

Combine like terms: 0 + -1 = -1
-4b = -1

Divide each side by '-4'.
b = 0.25

Simplifying
b = 0.25
Subproblem 2
Set the factor '(7 + -1b)' equal to zero and attempt to solve:

Simplifying
7 + -1b = 0

Solving
7 + -1b = 0

Move all terms containing b to the left, all other terms to the right.

Add '-7' to each side of the equation.
7 + -7 + -1b = 0 + -7

Combine like terms: 7 + -7 = 0
0 + -1b = 0 + -7
-1b = 0 + -7

Combine like terms: 0 + -7 = -7
-1b = -7

Divide each side by '-1'.
b = 7

Simplifying
b = 7
Solution
b = {0.25, 7}